WEBVTT
Kind: captions
Language: en

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&gt;&gt; Welcome to the Cypress
College Math Review

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on Difference Quotients.

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Here's the graph of
a function, y = f(x).

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A secant line is a line
through two points on a curve.

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Here's our two points.

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Delta x is a change in x.
So we have our first point

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with coordinates x, f(x)
and our second point

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with coordinates
x + delta x and f

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of the quantity x + delta
x. We want to find the slope

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of the line through
those two points.

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Here's the formula for slope.

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Now let's apply it.

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So the slope will be rise
over run, so the change

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in the y coordinates over the
change in the x coordinates,

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which gives us the formula
for the difference quotient.

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So the difference quotient is
the slope of the secant line.

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A lot of instructors, instead
of using delta x, use h,

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and that's what we'll
use in the problems.

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So instead of using
delta x, we will use h,

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so this is the formula
that we will use

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for the difference
quotients in the problems.

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Let's find the difference
quotient for this function.

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Here's our formula we're
going to need to use.

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Let's first find f of the
quantity x + h. So we're going

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to replace the variable
with x + h. We distribute

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and we get 5 x + 5 h. Now we
want our difference quotient.

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So we have f of the
quantity x + h

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minus f(x) all over h. This
is a really good idea.

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Brackets minus brackets
all over h. What do you put

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in the first brackets?

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Well, f of the quantity x + h,

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so that would be 5 x +
5 h - 7 in this case.

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What goes in the
second brackets?

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The original function.

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Now get rid of the brackets.

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So 5 x + 5 h - 7,
distribute the negative,

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so we have negative
5 x + 7 all over h,

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then we have positive 5 x - 5
x, negative 7 and positive 7,

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so we get 5 h over
h. The h's cancel,

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so we get 5 with
the restriction,

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of course, that h cannot be 0.

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Let's find the difference
quotient

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for this quadratic function.

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Every time you see an x, you're
going to replace it with x + h.

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And now we simplify
the right-hand side.

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Watch out, exponents
before multiplication,

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so we need to square
out this binomial.

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You cannot distribute the 3.

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Exponents come before
multiplication.

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So we square out the binomial.

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What do you get when you
square out a binomial?

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When you square out
a + b, you get what?

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A squared + 2 a b
+ b squared, right?

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So in this case, that would
be x squared + 2 x h or h x,

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either one, + h squared.

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Now I distribute the negative
2, so negative 2 x - 2 h + 3.

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Now we distribute the 3.

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And any time you change
what you're doing,

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you need to change your
label on the left-hand side.

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Now we're doing something else.

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We have to change our label.

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Now we're doing the whole
difference quotient,

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so we have to change our
label on the left-hand side.

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So we wrote down our label.

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Our new label is
the whole formula

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for the difference quotient.

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Brackets minus brackets.

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So we have the brackets
minus brackets all

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over h. What do we put
in the first brackets?

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f of the quantity x + h,
what we were just working on.

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What do we put in
the second brackets?

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The original function.

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Now we get rid of the brackets.

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So we distribute the negative.

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So we have a positive
3 x squared

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and a negative 3 x squared.

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We have a negative 2 x

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and a positive 2 x. We have a
positive 3 and a negative 3.

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Now we can factor out an h
from every term that's left

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and we're left with 6 x + 3 h
- 2 all over h. The h's cancel,

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so we're left with 6 x + 3 h

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minus 2 with the restriction
that h cannot be 0.

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So in this case, f

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of the quantity x + h
really can't be simplified.

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So here we go with the
difference quotient.

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So brackets minus
brackets, and in this case,

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the brackets don't
serve any purpose.

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All right, there's
two different ways

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to simplify this complex
fraction, and I'm going

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to do the problem twice so you
can see the two different ways.

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The first way is to
multiply it by the number 1

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which eliminates the
complex fraction.

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So I determine the LCD
of these fractions,

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and the least common denominator
would be x times the quantity x

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+ h. So I multiply the numerator

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and the denominator
by that expression.

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Of course, you can only multiply
an expression by the number one,

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and that's equal to
number one, distribute this

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to the first term in the
numerator, which gives me 3 x,

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distribute it to the
second term in the numerator

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and it gives me 3 times
the quantity x + h.

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In the denominator, it's
h times x times x + h,

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and it's all factored
and you want it factored,

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so we leave it like that.

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In the numerator, we distribute
the negative 3, 3 x - 3 x,

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so we have negative 3 h over h
x times x + h. The h's cancel,

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so we end up with negative 3

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over x times the quantity
x + h with, again,

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the restriction that
h cannot be 0.

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Referring back to
the same problem,

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to add or subtract fractions,

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where the least common
denominator is simply the

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product of the denominators,
you just cross-multiply, yes,

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a times d + b times c
over b times d, yes,

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to add fractions, okay?

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So we'll do that here.

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3 times x minus, in this case,
3 times the quantity x + h all

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over x times the
quantity x + h, yes.

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Now, I'm dividing by h. I
really don't want to do this all

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over h. That gives,
again, a complex fraction.

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So to divide by h,
that's the same thing

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as multiply by 1 over h, yes?

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Well, why write it like that?

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Multiply it by 1 over h.
Why don't I simply write it

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as h times it, yeah?

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Multiply h times
the denominator.

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Good. And then we do the
same thing we did earlier,

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since we've already done this
problem, and we get negative 3 h

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over h x times the quantity
x + h. The h's cancel

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and we get negative 3 over
x times the quantity x + h

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with the restriction
that h cannot be 0.

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Here are some problems
to try on your own.

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Pause the video, try these
problems, then restart the video

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to check your answers.

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Here are the answers
to the problems.

