WEBVTT

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&gt;&gt; Welcome to Atoms
and Elements, Part 3.

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In this video lecture, we are
going to look at ionic compounds

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as oxidation and reduction
reactions to form the ions.

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And so this will just be a
very preliminary introduction

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to oxidation and reduction
that we'll continue to build

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on throughout the course.

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Let's get started.

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All right.

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So we, in our last video,

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we learned that ionic
compounds form

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from the transfer of electrons.

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So we learned that the
metals lose electrons, right?

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To form the cations.

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And the non-metals gain
electrons to form the anions.

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All right?

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Now, the overall
charge on each side

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of the reaction must be equal.

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So in chemical reaction, we
have reactants on the left

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and products on the right, and
then there's our reaction arrow.

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So you can think of
that reaction arrow

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like an equal sign.

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All right?

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And we can think of, chemical
reactions are like a blending

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of chemistry, English and math.

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So when we look at a chemical
reaction, we can treat it

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like an algebraic expression.

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[ Pen scratching ]

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All righty.

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And then there's
a little mnemonic

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that can help us understand
oxidation and reduction.

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There's two of them.

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There's "LEO says GER" or
the other one is "OIL RIG".

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So as I explain oxidation
and reduction,

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I'll show you how these
sayings can help you.

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Right? So first we'll
focus on oxidation, right?

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So here it is, LEO, loss
of electrons, whoops.

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Loss of electrons is oxidation.

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Right? LEO.

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All right?

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Or the OIL would be
oxidation is loss.

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Right? So there's our LEO.

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So here we have sodium, as
a pure element and we know

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that pure elements
have no charge,

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and we know that it likes,
it has one valence electron,

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so here is the lost electron.

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Alrighty. So, one thing

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that sometimes students
think is a little strange is

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that we lost the electron,
but we put the plus.

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That's because in
chemical reactions,

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we only have addition, we
never have subtraction.

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The subtraction would be
in the charge, all right?

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So here's our lost
electron, so here's LEO,

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the lost electron means this
is an oxidation reaction.

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And here we go about
balancing the charge, right?

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The sodium was a zero,
was neutral on the left,

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treat the reaction
arrow as an equal sign;

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there's our sodium
ion, that was plus 1,

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and then there's the
plus from our reaction.

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And so you can think of
it just as "and", right?

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So everything is
like "and, and, and".

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And then the electron, of
course, has a minus 1 charge.

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So plus 1 and minus
1 equals zero, right?

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So the overall charge
on the left is zero,

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and the overall charge
on the right is zero.

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So there's our oxidation
reaction.

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Now we've been working

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to memorize the variable
charge metals,

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and this will help us
understand why they have more

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than one charge, right?

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So here we have the
pure element iron,

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and pure elements
are always zero.

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But then the iron can either
lose 2 electrons or 3 electrons.

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Right? So here's those
lost electrons, right?

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Right is oxidation.

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So there's our LEO, and
then we look, so that's why

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like for sodium, we just say

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that this is a sodium
ion, and everybody knows.

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But if we say iron ions, people
will be like, "Well which one?"

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So that's why we have to have
those Roman numerals, right?

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This is iron(II), and
then this is iron(III).

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And if we were to go deeper into
the chemistry, we would learn

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that iron(II) and iron(III)
have very different chemistries.

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So it's important to
distinguish between them

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with the Roman numerals
when we discuss them.

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And then just to
double check, right?

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Overall charge, we started with
a zero, with the pure element,

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and then either way, right?

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So if we, we'll just do
this one here, right?

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Iron was plus 3, and then we
had 3 electrons, so once again,

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the charge on the left equals
the charge on the right.

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All right?

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So that's oxidation
at its simplest level,

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and that's a great
place to start.

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As we can see here
with the iron, right?

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This iron plus 2, iron
plus 3 is involved in a lot

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of biochemical reactions,
so we'll be coming back

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to this, again in the future.

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Now let's look a little
more closely at reduction.

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So now this is right, gaining,
so this would be our non-metals,

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like Sulphur is a
non-metal, right?

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Here's our GER, gaining
electrons is reduction.

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So there's our GER, right?

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Or RIG, for the RIG,
reduction is loss of electrons.

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So there's the RIG version.

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All right?

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So GER, OIL RIG or LEO says GER.

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Okay. So now we're
gaining electrons,

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so here they are, right?

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Gained electrons, right there.

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And that's pretty much it.

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So let's just double check,

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see how we're doing
on our charge, right?

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So Sulphur is pure, it's zero,

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and now it's gaining
2 electrons,

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so that would be minus 2.

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Our reaction arrow is our equal,
and then we're forming sulfide,

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the anion sulfide,
which has a minus 2,

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so I think at this point,
we can just cover this up,

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and minus 2 equals
minus 2, right?

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So when we have chemical
reactions, the charge,

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the overall charge for
each side balances.

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Now, you know, this is a
little bit of continuity.

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I don't know what
to do about it,

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so we're just going
to go for it.

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Amongst the non-metals,
we have what are called

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diatomic elements.

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And you'll learn more about
these in a future video.

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But the main thing is that
these elements are all

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in their pure form.

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In their pure form,
they're like Siamese twins.

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They are going to stay together.

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So when we look at the-
and they're non-metals,

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so they want to gain electrons.

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So here we have,
we'll do chlorine.

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Here's chlorine in its
pure form, so it's neutral,

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and then we've learned,
right, that chlorine

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when it reduces,
it forms chloride.

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Right? But because of the 2
here, we actually have to allow,

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we have to count
the atoms, and so,

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to balance the charge, right?

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Of our neutral chlorine
molecule,

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forms 2 chlorine anions.

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We are going to have
to gain 2 electrons.

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All right?

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And once again, right?

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The charge is going to
balance, because we have zero

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and then we would have minus
2 equals minus 2, right?

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Because we have 2
chlorides altogether.

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Right? The 2 in front
says we have 2.

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Alrighty. Okay.

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So there is the basics of
oxidation and reduction.

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So now let's put this
altogether and practice it a bit

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to make sure we understand
what's going on.

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All right.

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So, as I mentioned, whether the
electrons are gained or lost,

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they are always added
to the reaction.

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So, gained electrons, right,
appear on the reactant side.

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So if we had copper, 2 plus,
and it gained 1 electron,

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it would go to copper
plus, right?

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So there's our reduction.

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And just making a plug for those
variable charge metals here,

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right?

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Has to have, copper 2 has
to have the Roman numeral,

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because it can exist in more
than one oxidation state.

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So even though this is
reduction, oxidation

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and reduction go together, so
we call them oxidation states.

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And then the loss
of electrons, right?

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Appears on the product side.

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So let's look at an
oxidation reaction.

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So if we had iron 2 plus,
oxidizing to iron 3 plus, right?

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There's our lost electron,

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and we've already named
those on the previous page.

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All right.

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So this would be a good
place to pause the video

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and answer these next set
of questions, on your own,

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and then restart the video
and see how you're doing.

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What we want to do is we want
to add the correct number

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of electrons to either the
reactant or the product side.

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I left a big gap, so
try not to give it away.

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Classify the reactions as
oxidation or reduction,

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and then for our ions,

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let's just practice
our ion nomenclature.

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All right, so I'll give
you a minute to pause.

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All right, let's
see how you did.

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Okay. So step 1, add the correct
number of electrons, right?

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So, remembering that
electrons, right?

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Electrons are negative,
so if we have a zero,

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and a positive, right?

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We're going to have to add
2 electrons to the right,

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so these are the lost electrons.

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So since they're lost electrons,
this is an oxidation reaction,

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and then this would
be a magnesium ion.

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Okay. Now let's look
at the next one.

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Here is nitrogen, and
now we have nitride.

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So we have zero on the left, and
we have minus 3 on the right,

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I have two of them, minus 6.

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So overall, there's minus
6 on the right hand side,

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and there's zero on
the left hand side.

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So we are going to have
to add 6 electrons.

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So here they were lost,
and here they're gained.

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All right?

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So gaining electrons,
GER, right?

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That's reduction.

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Okay. So the nitrogen
would gain 6 electrons

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to make two nitride ions.

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And when nitride, as
soon as we see the

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"-ide" we know it's an ion.

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[pen scratching] Okay, so
it's not so essential, right?

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Here we have the magnesium
element and the magnesium ion.

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So then it's important
to write "ion".

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But as soon as we
have the suffix,

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-ide, everyone will know.

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Okay, let's look
at the last one.

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Here we have chromium
6 and chromium 3.

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So to balance the charge, right?

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This has more positive,
so we would need

00:12:47.986 --> 00:12:50.126 A:middle
to add 3 electrons here.

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So once again, we're
gaining electrons,

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so gained electrons
is reduction, and last

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but not least, just to kind

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of really emphasize why we need
those Roman numerals, right?

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So this would be chromium(VI)
and as soon as we write the

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"VI", everybody knows
it's an ion,

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and then here chromium
1, 2, 3; chromium(III).

00:13:22.896 --> 00:13:23.836 A:middle
All right?

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So if there's a Roman numeral,
or a suffix, we don't have

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to worry about saying "ion"
but for those fixed charge,

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it's good for clarity.

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Okay, so that finishes
up our introduction

00:13:36.446 --> 00:13:38.626 A:middle
to oxidation and reduction.

00:13:39.016 --> 00:13:40.396 A:middle
Now would be a great time

00:13:40.396 --> 00:13:42.546 A:middle
to work a couple
post-video practice problems

00:13:42.546 --> 00:13:44.096 A:middle
to reinforce your understanding.

