WEBVTT

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&gt;&gt; Welcome to the Cypress College math
review on solving simple linear equations.

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Objective one.

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Solving linear equations
using properties of equality.

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So we're trying to solve an equation.

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So our goal is to get x on one side,
isolate it, and simplify the other side.

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We're going to use the addition

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and multiplication properties
of equality to help us do this.

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Let's say that a, b and c are real numbers.

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This property a plus c equals
b plus c is equivalent

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to a equals b is called the
addition property of equality.

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This property tells us that
you're allowed to add

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or subtract the same quantity
to both sides of an equation.

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ac equals bc is equivalent to ab is the
multiplication property of equality.

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This tells us that you can multiply or divide
the same quantity to both sides of an equation.

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We will use these two properties
in solving equations.

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Example. Solve for x. x minus 7 equals 3.

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So to solve for x, we need to get x by itself,
so we need to get rid of this minus 7 deal.

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What do we do?

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Well, we use the addition
property of equality and we add 7.

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Well, if you do it to one side, you must
do the exact same thing to the other side.

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So we need to add 7 to both
sides of the equation.

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Notice that minus 7 and plus 7 add up to 0 so
that disappears and 3 plus 7 is equal to 10.

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So on the left-hand side, all we have left
is x. And on the right-hand side we have 10.

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Therefore, x equals 10 and it's solved.

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Example. Solve for x. 5 plus x equals 1.

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Well, we wish to get x by itself,
so we need to get rid of the 5.

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That's a positive 5 out there
and that's a separate term

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from the x so we would need to subtract 5.

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If we do that to the left side,
we must do it to the right side.

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So we subtract 5 from both sides.

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A positive 5 and a negative 5 add up to 0.

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So the only thing left on the left-hand
side is x. 1 minus 5 is negative 4.

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So x is equal to negative
4, and we have our solution.

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Example. Solve for x. x divided by 8 equals 3.

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So we wish to isolate the x.
So we need to get rid of 8.

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x is being divided by 8.

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So the inverse operation
to dividing is multiply.

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So we need to use the multiplication property
of equality and multiply both sides by 8.

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A lot of students, when they're multiplying
fractions, like to write the 8 as 8 over 1.

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So now you see that the 8s cancel.

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So we get x on the left-hand side.

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x over 1 is just x. And then on the right-hand
side we have 8 times 3 and that gives us 24.

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So x is equal to 24.

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5 times x equals negative 20.

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So 5 is being multiplied times the x this time.

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The inverse operation to multiply is divide.

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So we divide both sides by 5.

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Notice that the 5s cancel on the left-hand
side so we just get x. x is isolated.

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On the right-hand side, we have negative
20 divided by 5 and that's negative 4.

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Therefore, x is equal to negative 4.

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Pause the video and try these problems.

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Objective two.

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Solving multi-step linear equations.

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Example. Solve for y. The variable
is not always going to be x.

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So our goal is to get y isolated by itself.

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We have negative 10 times y plus 15 equals 45.

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Think of your order of operations.

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You would multiply before you add, correct?

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But to solve an equation, you reverse your
order of operations to isolate the variable.

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So we will subtract 15 before
we divide by the negative 10.

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So first subtract 15 from both sides.

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Notice that positive 15 and
negative 15 add up to 0.

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So our left-hand side is just negative 10y.

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On the right-hand side, we
have 45 minus 15 and that's 30.

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Now we have negative 10 times y equals 30.

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The inverse operation to multiply
is divide which means we need

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to divide both sides by negative 10.

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The negative 10s on the left-hand side
cancel which just gives you 1y or just y.

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On the right-hand side, 30 divided
by negative 10 is negative 3.

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Therefore, y is equal to negative 3.

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Example. Solve for x. x divided by
negative 2 plus 8 is equal to 11.

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We wish to isolate x. We
reverse our order of operations,

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and we need to get rid of the plus 8 first.

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Since it's plus 8, we would subtract 8.

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So we subtract 8 from both sides.

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Positive 8 and negative 8 add up to 0.

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So we just have x divided by
negative 2 on the left-hand side.

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And 11 minus 8 is equal to 3.

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Now we have x divided by negative 2.

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We wish to get rid of the negative 2.

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Since x is being divided by negative 2, the
inverse operation to divide is multiply.

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So we multiply by negative 2.

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What we do to one side we
have to do to the other side

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so we multiply both sides by negative 2.

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Since we're multiplying fractions,
we'll go ahead

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and write the negative 2 as negative 2 over 1.

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And you can see that the negative 2s cancel.

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So we just get 1x equals negative 2 times 3
which is negative 6 so x equals negative 6.

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Example. Solve for x. 3x
plus 7 equals 5x plus 7.

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In this equation, we have variables on
both sides and numbers on both sides.

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So we need to get all of the x's on one side
and all of the numbers on the other side.

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So first let's move the x's.

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I choose to move the x's to the right side.

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So I'm going to move the 3x.

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It doesn't matter.

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You can choose either side.

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So we would subtract 3x from both
sides because that's a positive 3x.

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When I subtract 3x from positive 3x, I get 0.

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So I have 0 plus 7 equals.

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On the right-hand side, I have 5x minus 3x
which is 2x and I still have the plus 7.

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Now I need to move the 7 to the left-hand
side because I want to get x by itself.

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So I subtract 7 from both sides.

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On the left-hand side, 7 minus 7 is 0.

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On the right-hand side, I
have also 7 minus 7 is 0.

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So I have 2x plus 0 which is just 2x.

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I still do not have x by itself.

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There is a 2 that's being
multiplied times the x so I need

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to do the inverse operation which is divide.

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So I divide both sides by 2.

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0 divided by 2 is 0.

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And on the right-hand side
the 2s cancel so I get 1x.

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Well, that's just x so x is equal to 0.

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And you can turn it around and
put the x on the other side.

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Example. Solve for x. 5x
minus 8 equals 6x minus 1.

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Once again we have variables on both sides and
numbers on both sides, so we have to choose

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which side we want to put the x's on.

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I choose the left-hand side this time.

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So I'm going to move the
6x to the left-hand side.

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Since it's a positive 6x,
I'm going to subtract 6x.

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I subtract 6x from both sides.

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5x minus 6x is negative 1x.

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So on the left-hand side
I have negative x minus 8.

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On the right-hand side, 6x minus 6x
is 0 and 0 minus 1 is negative 1.

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Now we reverse our order of
operations to isolate the x.

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So since we have subtract 8, we need to add 8.

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Add 8 to both sides.

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Subtract 8 and add 8 gives us 0 so we have
negative x plus 0 on the left-hand side.

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On the right-hand side, we have negative 1 plus
8 and that's 7 so negative x is equal to 7.

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We still do not have x isolated.

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We need to get rid of the negative and
that's the same thing as a negative 1.

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So let's divide both sides by negative 1.

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A negative divided by a negative is a
positive so we get 1x on the left-hand side.

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On the right-hand side, 7 divided
by negative 1 is negative 7

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so we get that x is equal to negative 7.

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Pause the video and try these problems.

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Objective three.

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Solving linear equations that can be
simplified by combining like terms.

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Example. Solve for x. 1 plus 4x plus 2
is equal to negative 3 plus 2x plus 14.

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So we need to simplify each side of the
equation before we start moving things around.

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So on the left-hand side of the equation
we have the like terms of 1 and 2.

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So 1 plus 2 is equal to 3.

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So on the left-hand side we have 3 plus 4x.

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On the right-hand side, we
have negative 3 plus 14.

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Those are like terms.

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We can add those up and get 11.

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So the right-hand side is 11 plus 2x.

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Now we need to move all of the x's to one
side and all the numbers to the other side.

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x's, I choose left side this time.

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So we're going to move the
2x to the left-hand side

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which means we need to subtract
2x from both sides.

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4x minus 2x is equal to positive 2x.

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On the left-hand side, we have 3 plus 2x.

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On the right-hand side, 2x minus
2x is 0 and 11 plus 0 is just 11.

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Now we reverse our order of
operations to isolate the x.

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So we subtract 3 first before
we divide by the 2.

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So we subtract 3 from both
sides of the equation.

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3 minus 3 is equal to 0 and we
get 0 plus 2x which is just 2x.

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On the right-hand side, we
have 11 minus 3 and that's 8.

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Now we have 2 times x is equal to 8.

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We need to isolate the x. The inverse
operation to multiply is divide.

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So we divide both sides by 2.

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See how the 2s cancel, and on
the left-hand side I get 1x.

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So we get that x is equal to
8 divided by 2 which is 4.

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Example. Solve for x. Negative 2 times
the quantity 3x minus 4 is equal to 2x.

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Any time you have parentheses in an equation,

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you must get rid of the parentheses
before you start moving things around.

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So we will distribute the negative 2
to the 3x which gives us negative 6x.

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We distribute the negative 2 to the negative 4.

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That gives us positive 8.

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So the left-hand side is negative 6x plus 8.

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The right-hand side is just 2x.

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Now you can move the variables
to the left or to the right

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but since the right-hand side only has the
variable 2x, it would be quicker to move all

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of the x's to the right-hand side.

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So I'll add 6x to both sides
because I had a negative 6x.

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Negative 6x plus 6x is equal to 0
so the left-hand side is just 8.

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2x plus 6x is 8x.

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8 is being multiplied times x so the
next step is to divide both sides by 8.

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The 8s cancel.

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On the left-hand side I get 1
and the right-hand side I get 1x

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which is just x. You can write the x in the
answer either way on the left or the right

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so 1 equals x is the same as x equals 1.

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Example. Solve for k. The opposite

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of the quantity 6k minus 5 minus the quantity
negative 5k plus 8 is equal to negative 3.

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So since we have parentheses, our first
goal is to get rid of the parentheses.

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A negative in front of a parentheses is the
same thing as negative 1 times the parentheses.

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So we're going to distribute a
negative 1 to each of these parentheses.

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The 6k inside the first parentheses will become
a negative 6k when we multiply it by negative 1.

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Subtract 5.

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Well, that will become add 5 when
we distribute the negative 1.

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And negative 1 times negative
5k gives us positive 5k.

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Negative 1 times positive 8 gives us negative 8.

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And now we have the parentheses all gone.

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Now we're going to have like terms.

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On the left-hand side, we have a negative
6k and a 5k which adds to a negative 1k.

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And we also have 5 minus 8.

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Those add up to negative 3.

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Now we wish to get k by itself.

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So the first step would be to add 3 to
both sides because we have a minus 3.

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Minus 3 plus 3 is equal to 0.

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So we get negative k on the left-hand side.

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On the right-hand side, negative
3 plus 3 is equal to 0.

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We still do not have the k isolated.

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We need to get rid of the negative.

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That's the same thing as negative 1k.

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So we're going to divide
both sides by negative 1.

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Negative k divided by negative 1.

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Negative divided by a negative is a positive
so we just get k on the left-hand side.

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0 divided by negative 1 is 0.

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Therefore, k is equal to 0.

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Example. Solve for m. Negative 3 times the
quantity m minus 4 plus 2 times the quantity 5

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plus 2m is equal to 29.

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So our first goal is to get
rid of the parentheses.

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We distribute the negative
3 to m and get negative 3m.

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Negative 3 times negative 4 gives us plus 12.

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2 times 5 gives us 10.

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And 2 times 2m gives us 4m.

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Now we need to add like terms on
the left-hand side of the equation.

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Negative 3m and a positive
4m gives us positive 1m.

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Positive 12 and positive 10 give us 22.

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Now we have m plus 22 equals 29.

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To get the m by itself, we need
to subtract 22 from both sides.

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So we get m equals 29 minus 22
which is 7 so m is equal to 7.

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Pause the video and try these problems.

