WEBVTT
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Language: en

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&gt;&gt; Welcome to the Cypress College
Math Review on Completing the Square.

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Our first objective deals
with the square root property.

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Before we get to what the
square root property is we want

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to review first what a quadratic
equation in standard form looks like.

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Suppose a, b, and c are real numbers
such that a does not equal to zero.

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Then any equation that could be written

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in the form ax squared plus bx
plus c equals zero is considered

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to be a quadratic equation in standard form.

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The quadratic part is because you have a term
that has its variable with an exponent of two.

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What makes it standard form
is that it's equaling zero.

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So with that in mind let's now look
at what is the square root property.

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Suppose k is a real number.

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If x squared equals k, then x equals the square
root of k or x equals negative square root

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of k. This may also be written as x
equals plus or minus the square root of k.

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So we will use the plus or minus
symbol to represent the positive

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and the negative version of our square root.

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While we still need to simplify the radical
we now have some notation that's a little bit

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more compact.

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Now let us solve some quadratic equations
actually using the square root property.

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In our first example we have x
squared plus 3 equals negative 15.

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Before you can actually use the
square root property you need

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to isolate the square term first.

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So here x squared is that square term and in
order to get it alone on the left hand side

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of the equation we need to
subtract three form both sides.

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This leaves us with x squared
equaling negative 18.

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Once we have x squared alone we are now
ready to use the square root property,

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which says x sill be equal to plus or
minus the square root of negative 18.

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Once we have done all this we can
now focus on simplifying the radical.

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One of the first things we can do when
it comes to simplifying the square root

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of negative 18 is remember that i
equals the square root of negative 1.

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So we can actually have that negative
inside of our radical leave as i.

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So we can now rewrite our statement as x equals
plus or minus i times the square root of 18.

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Now we can focus all of our attention on
just simplifying the square root of 18.

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Our goal is to try to find what
perfect squares make up the number 18.

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So let us simplify the radical
by noticing x equals plus

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or minus i times the square root of 2 times 9.

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The reason why we may want to show our
statement this way is so that we can see

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that we have the perfect square nine
inside of our square root and we know

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since the square root of 9 is 3 we
can simplify by saying x equals plus

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or minus 3 i times the square root of 2.

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Since we can't simplify any further
we're now ready to write our solution set

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which can be written as an open brace, and from
here we just list our solutions that we found.

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So we write negative 3 i times the square root
of 2 and positive 3 i times the square root

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of 2, and then we close it with a brace.

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Let's try another example.

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In this one we're going to notice that our
square term is no longer just a single letter,

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it actually contains an expression so
let's read what we have to look at.

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We have here the quantity 4 m plus 5 being
squared, then we subtract 8 equaling 20.

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So our goal is still the same as it was
before; we can't use the square root property

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until we isolate the squared term.

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Here 4 m plus 5 is the quantity that is being
squared so that is what we want to get alone.

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First step we need to add 8 to both sides.

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This leaves us with 4 m plus
5 quantity squared equals 28.

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Here we can finally use the square
root property which has the inside

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of what was being squared staying the same,

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4 m plus 5 equals plus or
minus the square root of 28.

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Before we focus our attention on
solving for m on the left hand side

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of the equation let's simplify the
radical first, this will just allow it

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so that we don't forget to do it
later on and we're going to have

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to do it anyway so let's just do it right now.

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Let's keep 4 m plus 5 on the left equaling
plus or minus the square root of 4 times 7.

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Why we're writing 28 in this way is
because we notice 4 is a perfect square

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because the square root of 4 is 2, leaving
the 7 left over inside of our square root.

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So now we can rewrite our
statement as 4 m plus 5 equals plus

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or minus 2 times the square root of 7.

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Since we can't simplify the radical
any further we can now focus the rest

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of our attention on solving for the variable.

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Here the first thing we need to do
will be to subtract 5 from both sides

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so we get 4 m equaling negative 5 plus
or minus 2 times the square root of 7.

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After that we want to divide both
sides of our equation by the number 4,

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which leaves us with m equals negative 5 plus

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or minus 2 times the square root
of 7 all being divided by 4.

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Once we have this we are now ready to
write our final answer as a solution set.

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So our solution set will take the form of open
brace negative 5 minus 2 times the square root

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of 7 all divided by 4, and
we have our second solution

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of negative 5 plus 2 times the square root of 7
all divided by 4; then we close it with a brace.

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Pause the video and try these problems.

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In objective two we're going to
review perfect square trinomials.

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A perfect square trinomial is a
trinomial which is a three term polynomial

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that when you factor it results
in a binomial being squared.

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So if you have a trinomial of the form a
squared plus 2 ab plus b square it will factor

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as a binomial a plus b quantity squared.

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If instead of addition for your middle term
you actually have subtraction the factorization

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changes to a minus b quantity squared.

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The way that you can remember this
is that the sign in the middle

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of the trinomial always match the sign in the
middle of your binomial when it's factored.

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Let us try some examples.

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Factor the perfect square trinomial.

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In part a we have x squared plus 18 x plus 81.

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Well we first want to verify does this even have
the structure of a perfect square trinomial?

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How we can go about doing this is setting up
some parenthesis that actually shows the formula

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for a perfect square trinomial and if it checks

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out we can then factor it using
those pieces that we found.

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So let's begin by writing some parenthesis,

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leave some space inside, and
put a square on the outside.

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Then we'll write a plus 2 times and
we'll write two more sets of parenthesis,

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leaving the insides blank for now,
plus a set of parenthesis squared.

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Now we're going to go in
and fill all these blanks.

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The first set of parenthesis we are going to ask
ourselves what would I need to square in order

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to get the first term of x
squared in the original trinomial.

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That would have to be a x because x
when you square it gives you x squared.

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Now before we check the middle
I always encourage people to go

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to the back and let's check the last term.

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Let's see there that what would you
have to square in order to get 81.

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Well 9. So now that you see that the
first term and the last term are matching

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up let's take what was in those two sets of
parenthesis and put them into the middle set

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of parenthesis and we're going to check is it
true that 2 times x times 9 does it equal 18 x,

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and if the answer is yes like it is

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in this example then what we have is
actually a perfect square trinomial,

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which means we can now factor this by taking
our x, our 9, and since the sign in the middle

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of the original trinomial was a plus
sign we also will have a plus sign.

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So now we can write our factorization
as x plus 9 quantity squared.

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For our next example we're not just going
to have the leading coefficient being 1,

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what happens if the leading
coefficient is another number?

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So in example b we have 9 c
squared minus 66 c plus 121.

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We're going to set up everything the same
way as we did before but now it's just going

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to be a matter of what are the pieces that
we need to create that above trinomial.

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So let's set up our actual parenthesis,
so we equal a set of parenthesis squared.

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Since we have subtraction
of that 66 c we're going

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to write minus 2 times we'll
write our two sets of parenthesis,

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plus a set of parenthesis squared.

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Now we're going to check that first term.

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In order to get 9 c squared
wouldn't you have to use a 3 c?

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To get that 121 for the last term
wouldn't you have to square 11?

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So now we can take 3 c, now we can take our
11, fill in the middle two sets of parenthesis

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and check is it true that negative
2 times 3 c times 11 does it

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in fact equal negative 66 c. Well negative
2 times 3 c would give you negative 6 c

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and negative 6 c when you multiply by
11 does in fact give you negative 66 c.

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So again we have a perfect square
trinomial so we can take the 3 c and the 11,

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we can write them now taking the subtraction
with us to get 3 c minus 11 quantity squared.

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We are now ready for completing
a perfect square trinomial.

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We can make x squared plus bx a
perfect square trinomial by adding

00:10:54.086 --> 00:10:58.106
to it 1/2 times b and then
we square that result.

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The b in this formula is coming
from the number in front of x;

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this is known as the linear coefficient.

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This is only possible though when the leading
coefficient, the number that's in front

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of the x squared, is positive 1, so we will
have to be aware of that when we start playing

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with different examples in the future.

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Let's start now with an example of this.

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Find what number must be added to the expression
in order to make it a perfect square trinomial.

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Then factor the trinomial.

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We have x squared minus 8 x. The b value we have
is negative 8, so we will take 1/2 multiply it

00:11:40.406 --> 00:11:43.546
by negative 8 and we will square that result.

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We could jump straight to the simplified
answer here but it's actually going

00:11:49.226 --> 00:11:51.216
to benefit us by showing the middle step.

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This will allow us to use a shortcut
when it comes to that factoring step.

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So let's take half of negative
8, which is negative 4,

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we'll square it; so negative
4 squared equals 16.

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Sixteen is the number that is going to complete
the perfect square trinomial for our expression,

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so we write plus 16, and
now we're ready to factor.

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But when it comes to factoring
this is where we can take advantage

00:12:18.026 --> 00:12:19.836
of that shortcut that I've mentioned earlier.

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Here we can write the letter of the
problem, which is x, and the number you need

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to factor this will be the number
we had before we squared it.

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So since we had negative 4
we're going to write minus 4.

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We will put this in parenthesis and
then put a power of 2 on the outside.

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So we have x minus 4 quantity squared.

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If we really wanted to check this multiplying

00:12:45.886 --> 00:12:51.960
out x minus 4 quantity squared will
get us the x squared minus 8 x plus 16.

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Pause the video and try these problems.

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Objective three, completing
the square when a equals 1.

00:13:13.166 --> 00:13:17.066
In this example we're going to solve the
quadratic equation by completing the square.

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What we have is x squared
minus 4 x minus 10 equals zero.

00:13:23.296 --> 00:13:26.796
Since the leading coefficient
is already 1 all we need

00:13:26.796 --> 00:13:29.776
to do first is isolate the variable terms.

00:13:30.126 --> 00:13:35.126
This means get x squared minus 4 x
alone on one side of the equal sign.

00:13:35.576 --> 00:13:39.236
Well in order to do this we
need to add 10 to both sides.

00:13:39.746 --> 00:13:44.736
So by doing so we end up getting
x squared minus 4 x equaling 10.

00:13:45.576 --> 00:13:49.246
Once we have the variable terms
alone on one side we're ready

00:13:49.246 --> 00:13:51.106
to do that completing the square step.

00:13:51.106 --> 00:13:56.086
We want to try to figure out what number we need
to add to our expression on the left in order

00:13:56.086 --> 00:13:58.146
to make it a perfect square trinomial.

00:13:58.506 --> 00:14:03.146
This is where we use 1/2 times
b and we square that result.

00:14:03.636 --> 00:14:09.036
So to complete the perfect square trinomial
in this problem we take 1/2 and we multiply it

00:14:09.096 --> 00:14:14.246
by the b value here, which is negative
4, and we will square our result.

00:14:15.186 --> 00:14:18.456
In order to still use the shortcut
we will show the simplifying step,

00:14:18.626 --> 00:14:24.996
1/2 times negative 4 is just negative 2,
which we will square to get positive 4.

00:14:26.096 --> 00:14:29.986
Four is the number that we want to
now add to both sides of our equation.

00:14:30.646 --> 00:14:37.126
This leads us to x squared minus
4 x plus 4 equaling 10 plus 4.

00:14:38.026 --> 00:14:43.246
From here we're ready to factor the perfect
square trinomial that we created on the left

00:14:43.246 --> 00:14:46.166
and all we need to do to the
right is simplify the numbers.

00:14:46.786 --> 00:14:50.626
To factor the perfect square
trinomial we will write x,

00:14:51.176 --> 00:14:57.246
and since it was negative 2 before we squared
it that's what we'll write next, minus 2,

00:14:57.996 --> 00:15:03.016
put parenthesis around this so that we can
square the quantity, and what we will be equal

00:15:03.016 --> 00:15:06.646
to is 10 plus 4, which is just 14.

00:15:11.406 --> 00:15:15.306
Now that everything has been factored
and simplified we are now ready

00:15:15.306 --> 00:15:18.446
to use the square root property
to solve for the variable.

00:15:19.286 --> 00:15:27.146
To do this we write x minus 2 equals
plus or minus the square root of 14.

00:15:28.336 --> 00:15:34.116
Since 14 does not contain any perfect
square factors we leave our radical

00:15:34.116 --> 00:15:35.666
as the square root of 14.

00:15:36.266 --> 00:15:39.436
All we need to do now is add 2
to both sides of our equation

00:15:39.436 --> 00:15:45.276
so that we get x equals 2 plus
or minus the square root of 14.

00:15:46.136 --> 00:15:49.776
And our final step is to use solution
sets to represent our answers.

00:15:50.496 --> 00:15:57.256
So we write an open brace, 2 minus the
square root of 14, we'll write our comma,

00:15:58.160 --> 00:16:02.800
and then we write 2 plus the square
root of 14, and close it with a brace.

00:16:07.280 --> 00:16:10.520
Pause the video and try these problems.

00:16:19.040 --> 00:16:23.240
Objective four, completing the
square when a does not equal 1.

00:16:23.716 --> 00:16:27.516
In this example we're going to solve the
quadratic equation by completing the square

00:16:27.996 --> 00:16:32.986
but you're going to notice that our leading
coefficient is no longer a positive 1.

00:16:33.126 --> 00:16:39.106
Here we have 2 x squared plus
3 x minus 52 equaling zero.

00:16:39.106 --> 00:16:44.496
We're going to start of the same way,
let's isolate the variable terms first.

00:16:44.906 --> 00:16:48.776
To do this we'll just add 52
to both sides of our equation.

00:16:49.356 --> 00:16:54.336
This leads us to 2 x squared
plus 3 x equaling 52.

00:16:55.436 --> 00:17:02.176
From here we want to turn 2 x squared into just
1 x squared; in order to do this we're going

00:17:02.176 --> 00:17:09.006
to divide every term by the leading coefficient
a in the case when a is not equaling 1.

00:17:09.516 --> 00:17:14.716
So in our problem we're going to divide every
term on both sides of the equation by 2.

00:17:15.386 --> 00:17:21.306
So we'll divide 2 x squared by 2, we'll
divide 3 x by 2, and we'll divide 52 by 2.

00:17:22.146 --> 00:17:31.206
When we reduce each of the fractions as best
we can we get x squared plus 3/2 x equaling 26.

00:17:32.336 --> 00:17:36.416
Now we want to complete the
perfect square trinomial and solve

00:17:36.416 --> 00:17:38.356
for the variable as we did before.

00:17:38.896 --> 00:17:43.636
This is where we're going to use 1/2
times b and then square the result.

00:17:44.486 --> 00:17:50.486
So in our problem we're going to take
1/2, we multiply it by the b value 3/2,

00:17:50.636 --> 00:17:52.226
and then we'll square that result.

00:17:52.936 --> 00:17:59.986
Simplifying gets us 3/4 squared,
and then once we square we get 9/16.

00:18:04.586 --> 00:18:08.676
Nine sixteenths is now the number we're
going to add to both sides of our equation,

00:18:09.086 --> 00:18:20.666
so we write x squared plus 3/2
x plus 9/16 equals 26 plus 9/16.

00:18:21.836 --> 00:18:26.686
Once we've done this we can now factor the
perfect square trinomial that is on the left.

00:18:26.946 --> 00:18:30.376
This is absolutely when we want
to take advantage of our shortcut.

00:18:30.806 --> 00:18:40.376
Here we will write x, and since we had positive
3/4 we write plus 3/4 quantity squared.

00:18:41.366 --> 00:18:46.046
On the right we are going to have to do
some fraction addition where we will need

00:18:46.046 --> 00:18:52.666
to find a common denominator and then rewrite
the 26 plus 9/16 as a single fraction.

00:18:53.456 --> 00:18:57.966
After we have done this work
we end up getting 425/16.

00:18:58.846 --> 00:19:01.666
We are now ready to use the
square root property.

00:19:02.386 --> 00:19:08.196
To do it we're going to get
x plus 3/4 equals plus

00:19:08.196 --> 00:19:13.546
or minus the square root of 425 divided by 16.

00:19:15.036 --> 00:19:20.276
Before we move the 3/4 over, as always,
let us simplify the radical first

00:19:20.276 --> 00:19:21.706
so that we don't forget to do it.

00:19:22.536 --> 00:19:26.766
We have a property of radicals that
says whenever you have a quotient inside

00:19:26.766 --> 00:19:30.066
of a radical you can split it apart
so that you're taking the root

00:19:30.066 --> 00:19:32.716
of both the numerator and
denominator separately.

00:19:33.566 --> 00:19:35.836
The reason why we do this is because we want

00:19:35.836 --> 00:19:39.186
to make sure we don't have any
radicals left over in a denominator.

00:19:39.766 --> 00:19:47.826
In our problem we're going to have x plus
3/4 equals plus or minus the square root

00:19:48.226 --> 00:19:53.416
of 425 divided by the square root of 16.

00:19:53.956 --> 00:19:59.566
We can now simplify the numerator
to get 5 times the square root of 17

00:20:00.006 --> 00:20:02.686
and we can simplify the denominator to get 4.

00:20:03.306 --> 00:20:08.886
This leaves us with x plus 3/4 equals plus

00:20:08.886 --> 00:20:14.626
or minus 5 times the square
root of 17 divided by 4.

00:20:15.156 --> 00:20:20.736
We will now solve for x by subtracting
3/4 from both sides of our equation.

00:20:21.256 --> 00:20:26.646
This leads to x equals negative 3/4 plus

00:20:26.646 --> 00:20:32.366
or minus 5 times the square
root of 17 divided by 4.

00:20:33.416 --> 00:20:37.886
With x being solved we can now
write our final solution set.

00:20:38.186 --> 00:20:45.986
So we have negative 3/4 minus 5 times
the square root of 17 divided by 4

00:20:46.640 --> 00:20:53.280
and we have negative 3/4 plus 5 times
the square root of 17 divided by 4.

00:21:00.880 --> 00:21:03.520
Pause the video and try these problems.

