WEBVTT

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&gt;&gt; This is a tutorial
on Lab Number Five,

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Isometric Pictorials.

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Let's start the problem one.

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We're given the front, the
top front and right side view

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of the solid, and we're also
given an isometric grid,

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and what I've done here is I've
sketched using construction

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lines, the light blue lines,
the lines that are shown in the front view.

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So this is the image on
the frontal plane as shown

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in the front view here, and
I've done a similar thing

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for the right side view.

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Here's the right side view
and I sketch what I see

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on the right profile plane.

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And similarly for
the top view,

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and from this projected images
on the three principle planes,

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we're going to trying to
reconstruct the isometric.

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Now let's start with the plane

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in the front numbered
one, two, three, four.

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So I've located those

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in the right side view
one, two, three four.

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One, one, four here, and
two, three here based

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on the position along
the horizontal line

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with the front here, which means

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that this is 1 in the isometric
two, three, and four.

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All those four points are
exactly on the frontal plane

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as illustrated in the
top view and the front view.

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So I just try connecting
one, one, one and two,

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two and three, and
three and four.

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So I've located that plane,
one, two, three, four.

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So I've, I'm looking for the
isometric, plane by plane.

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Next, I'm going to
look for another plane.

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This one here, right,
one, two, three, four,

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I'm going to level
this five and six.

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Looking for five and six
in the right side view,

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this is the only possible
location of five comma six.

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They correspond at
the same point.

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Because they have to be
the same plane as one, two.

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So this must be five and this
must be six in the top view.

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Now based on the width,
depth, and height positions,

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these two points on the
isometric must be five

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and six right here, and five
should be connected to one

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as shown in the figure,
five connected to six,

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and then six connected to
two, and that agrees

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with the incline plane, the
edgeview of inclined plane, one,

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two, five, six as shown
in the right side view.

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Now, we can go to this skinny
rectangle in the top view,

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and I think it's pretty clear

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that this skinny rectangle is
all the way to the top as shown.

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I think shown in the front
view and the right side view.

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Now, next thing I'm going
to do is look for the,

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this incline plane here
or this incline line here

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as shown in the front view.

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So that's six, OK.

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That means that this,
there's a point six,

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six prime, six prime behind it.

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This must be seven.

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This must be seven in the front
and seven prime in the back.

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OK. So this must be seven and
seven prime in the isometric

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as well as six prime then.

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I can connect six to seven,
six prime to seven prime, OK.

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And seven to seven prime,

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and that skinny incline
rectangle is consistent

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with what's shown in the front
as well as the other two views.

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Next thing we're going to do
is what on this plane here

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that is shown in
the right side view.

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I'm going to call this
three, three prime.

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So there's a point that are
directly behind two prime

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and three prime directly
by two and three.

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So locating them the
front and the top as well.

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So the two must be, the two
prime must be directly two prime

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and directly below six, and the
three prime is directly behind

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three in the same depth
location as seven.

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So this must be the two prime,

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and this must be
the three prime.

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OK. So now I can connect
three with three prime, OK.

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Do the same thing,
connecting two to two prime.

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OK. Then six is directly
above two prime.

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Then two prime and three prime
are connected, and, finally,

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three prime and seven
are connected.

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So that incline plane,
two, two prime, three,

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three prime is actually at
the edgeview in the front.

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It's an incline plane.

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It's perpendicular to the
frontal plane.

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And I think that's about it.

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Hopefully, that makes sense.

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Now going to the last problem
is a little more complicated,

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and it might be more
difficult to visualize.

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So for things like this,
it's even more important

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to not initially visualize
what it looks like,

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but work on a claim by
claim, point by point.

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So we've labeled here claim one,
two, three, four, five, six,

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seven, eight, nine, ten, and
located one, two, three, four,

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five, six on the right
side as well, based

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on their location
along the height.

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Now, the top view location
of those points can be looked

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at by the projections and
also the projection along the

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miter lines.

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So the miter line
will allow us to.

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So, for instance, from
point one, one must be along

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that according to the right
side view, one has to be along

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that projection to the,
which means that this is .1.

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Then let's go to .2.

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Point 2 is directly
above here, but according

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to the right side view, it's
in the same depth as one.

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Therefore, this is .2.

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Then we connect one and two,
and take notice, and doing this,

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I'm simply locating points
based on the depth and the width

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that are given in the front
and the right side view,

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and I'm not visualizing
how the object looks.

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Going to .3 now, three is
directly above that line.

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Then three, according to
the right side view is here.

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Therefore, this must
be .3 right here,

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giving us Point 3.

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Connecting two and three.

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So, again, I'm locating
points systematically based

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on their projections.

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Going to four, this must be
the location of four based

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on the width and the depth,

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and then I just connect
three and four.

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OK. I am not visualizing what
the object looks like right now.

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Just connecting the,
this is five.

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The depth of five, according

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to the miter line
should be over here.

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So that must be five.

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Connect four and five.

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Go to six.

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Six is in the same
depth as five.

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So this must be six.

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OK. Connect five and six.

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Then go to seven.

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Seven is directly all
the way to the right,

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but the projection
of seven is here.

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So that's seven from
the right side.

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That's the depth. Connect
six and seven.

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Going to eight, it's also to
the right, but it's now also

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in the front according
to [inaudible].

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Connect seven and eight,
and then nine is all the way

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to the left, but it's
also on the front.

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So this is nine connect.

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Let's connect nine and eight.

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OK, and then let's go to ten.

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The projection of ten is here.

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OK. So that must be ten.

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Nine and ten, and then
connect ten and one,

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and we're done with the plane.

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OK. I can repeat the
same process, OK,

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to find the location

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of the other similarly
shaped plane in the back.

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It's just a mirror
image of what I'm seeing, OK.

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So it's going to look
something like this.

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And so six [inaudible].

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So that's the mirror image
of what we have in the front.

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Then let's just connect
them because I know based

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on the right side view that
those points are connected.

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OK. So it's not shaping,
taking shape.

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And then there's only a couple
of lines that are in the same.

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This line here, the
hidden line shown

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in the right side view, OK.

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Three, two, three,
two, three, five,

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and four to four prime will
be shown as hidden lines

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in the top view because they
are being hidden by planes

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that are higher,
and that's about it.

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Now, once you have this, you
can now go and start plotting

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on the isometric grid.

